anonymous
  • anonymous
How many 3 digit even numbers can be formed from the digits 1,2,3,4,5,6 1.If the digits are not repeated
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[n!/ (n-r)!r!\]\[\rightarrow 6! /(6-3)!3! =20\]
anonymous
  • anonymous
For the third spot, you only have 3 choices (2,4,6). For the rest of the two spots you have 5 choices. 5P2*3? maybe
Callisto
  • Callisto
1st, think of the last digit, as it is an even no. there are only 3 choices can fulfill the requirement Second, think of the 1st digit, it can be any number except the last digit, which has been chosen already, so you have 5 choices 3rd, think of the 2nd digit, it can be any number except the last digit and the 1st digit, which have been chosen already, so you have 4 choices finally , multiply the choices of each case together. that is 3x5x4 = 60 numbers not sure if it is correct

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Oh yeah, you can't repeat the digits.

Looking for something else?

Not the answer you are looking for? Search for more explanations.