• anonymous
A computer virus is trying to corrupt two files. The first file will be corrupted with probability 0.4. Independently of it, the second file will be corrupted with probability 0.3. Compute the PMF of X, the number of corrupted files. A = probability of corrupted first file B = probability of corrupted second file So, for X = 2, P(A and B) = 0.4 * 0.3 = 0.12 for X = 0, P(~A and ~B) = 0.6 * 0.7 = 0.42 for X = 1, P(A or B) = 0.4 + 0.3 - 0.12 = 0.58 ??? but it should be 0.46, what is wrong with my reasoning?
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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