anonymous
  • anonymous
Double checking work here. Solve 15x^4-14x^2+3=0 My answers are \[1/\sqrt{3}, - 1/\sqrt{3}\] \[\sqrt{3/5}, -\sqrt{3/5}\]
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
apoorvk
  • apoorvk
the last two are right the first two will be sqrt3 and -sqrt3
anonymous
  • anonymous
so i towuld be \[\sqrt{3}, -\sqrt{3}\] for the first two
apoorvk
  • apoorvk
yes exactly... re do it... at the factor (x^2-3)=0, i guess u made a mistake.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yea i think i messed up the fraction, inverted them probably on accident
anonymous
  • anonymous
no i actually double checked and the first part ± \[\sqrt{1/3}\]
anonymous
  • anonymous
±

Looking for something else?

Not the answer you are looking for? Search for more explanations.