anonymous
  • anonymous
Please help! f(x)= {-7x^2+6x for x less than 0 and 6x^2-2 for x greater than or equal to 0} Compute the left and right hand limits: x approaches 0
Mathematics
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katieb
  • katieb
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phi
  • phi
for x < 0, you have f(x)=-7x^2+6x what is f(x) when x is a small negative number approaching 0?
phi
  • phi
for x>0, f(x)= 6x^2-2 when x-->0 do you see that 6x^2 --> 0 and f(x)= 0-2= -2 in the limit?
anonymous
  • anonymous
Yes I see that now

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phi
  • phi
what do you get for left hand limit ? (x is the the left of 0 i.e. negative, but approaching 0)
anonymous
  • anonymous
I thought it would be 0 but it is not correct
phi
  • phi
-7x^2+6x approaches 0. Are you sure this is the correct expression?
anonymous
  • anonymous
Yes, maybe the system is glitching? Because I thought it would be 0, -2, and f'(0) DNE

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