Sadaf
  • Sadaf
Thrown Horizontally from Height with initial Velocity Vo.... initial condition y(t=0)=0, x(t=0)=0, the equations of motion is:dx/dt=Vo, dy/dt=0;d^2x/dt^2=0;d^2y/dt^2=-g Vx(t)=dx/dt= Vo; Vy(t)=dy/dt=-gt.... x(t)=Vot; and y(t)= -1/2 gt^2 a) What is the maximum height reached by the object? b) How long the object stays in the air? c) How far from its initial location the object hits the ground? d) With what velocity does the object hits the ground?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Shayaan_Mustafa
  • Shayaan_Mustafa
hello sadaf :) Sorry to say.. but this question is not able to understand. write it in easiest way. Thank you.

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