anonymous
  • anonymous
find coordinates of x/ y intercept and max or mini point on the grapg of these quad fuction. show answer by obtaining reasoing with sumbolic forms help: 9a ) f(x)=x(7-x) d) f(x)=-(x-3)(x+5) g) f(x)=2(x-3)(x-8)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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phi
  • phi
what's with reposting this?
anonymous
  • anonymous
my internet messed up
phi
  • phi
Try this one f(x)=-(x-3)(x+5) replace x with a 0 f(0)= -(0-3)(0+5) can you do the arithmetic?

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anonymous
  • anonymous
i dont remember how to
phi
  • phi
do the stuff in parens first (0-3) = ?
anonymous
  • anonymous
-3?
phi
  • phi
and (0+5) = ?
anonymous
  • anonymous
5
phi
  • phi
now -(-3)(5) multiply it out the - sign out front is the same as -1 -1* -3 * 5
anonymous
  • anonymous
-15
phi
  • phi
a minus times a minus is a plus
anonymous
  • anonymous
so it would 15
phi
  • phi
so you found f(0) and that is the y-intercept. now find the x - intercept. that is where f(x)= 0 or, in this case, -(x-3)(x+5) = 0 what x value makes this zero?
anonymous
  • anonymous
f=15 for the y itnecept?
phi
  • phi
y= 15 or f(0)= 15 is how you say it.
anonymous
  • anonymous
ok
anonymous
  • anonymous
so now how do i find x intecept
phi
  • phi
now find the x - intercept. that is where f(x)= 0 or, in this case, -(x-3)(x+5) = 0 what x value makes this zero?
anonymous
  • anonymous
3nd -5
phi
  • phi
so those are your x-intercepts
anonymous
  • anonymous
okay how would i write that
phi
  • phi
The parabola peaks at exactly between the two x-intercepts so find the average of -5 and 3 to get where it peaks.
anonymous
  • anonymous
how do i do that
phi
  • phi
you could mark them down and start counting from -5 to 3 and then go to the half way point.
phi
  • phi
or you could add them together and divide by 2
anonymous
  • anonymous
i got -1
phi
  • phi
next, we need to know is this a max or a min? Do you know? One way is put -1 in for x and figure out f(-1)
anonymous
  • anonymous
can u write it out
phi
  • phi
f(x)=-(x-3)(x+5) replace the x with a -1
anonymous
  • anonymous
ok how to solve
phi
  • phi
Here is a picture. |dw:1332534577178:dw|
anonymous
  • anonymous
okay i got the graphh
phi
  • phi
when you put x=-1 in what did you get? f(x)=-(x-3)(x+5) f(-1) = - (-1-3)(-1+5) now it is arithmetic
anonymous
  • anonymous
-4 and 4
phi
  • phi
now multiply -1(-4)(4)
anonymous
  • anonymous
16
anonymous
  • anonymous
?
phi
  • phi
that is the value at -1. You know the parabola is 0 at -5 goes up to 16 at -1 goes back down to zero at 3. So you have a maximum

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