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what's with reposting this?
my internet messed up
Try this one f(x)=-(x-3)(x+5) replace x with a 0 f(0)= -(0-3)(0+5) can you do the arithmetic?
i dont remember how to
do the stuff in parens first (0-3) = ?
and (0+5) = ?
now -(-3)(5) multiply it out the - sign out front is the same as -1 -1* -3 * 5
a minus times a minus is a plus
so it would 15
so you found f(0) and that is the y-intercept. now find the x - intercept. that is where f(x)= 0 or, in this case, -(x-3)(x+5) = 0 what x value makes this zero?
f=15 for the y itnecept?
y= 15 or f(0)= 15 is how you say it.
so now how do i find x intecept
now find the x - intercept. that is where f(x)= 0 or, in this case, -(x-3)(x+5) = 0 what x value makes this zero?
so those are your x-intercepts
okay how would i write that
The parabola peaks at exactly between the two x-intercepts so find the average of -5 and 3 to get where it peaks.
how do i do that
you could mark them down and start counting from -5 to 3 and then go to the half way point.
or you could add them together and divide by 2
i got -1
next, we need to know is this a max or a min? Do you know? One way is put -1 in for x and figure out f(-1)
can u write it out
f(x)=-(x-3)(x+5) replace the x with a -1
ok how to solve
Here is a picture. |dw:1332534577178:dw|
okay i got the graphh
when you put x=-1 in what did you get? f(x)=-(x-3)(x+5) f(-1) = - (-1-3)(-1+5) now it is arithmetic
-4 and 4
now multiply -1(-4)(4)
that is the value at -1. You know the parabola is 0 at -5 goes up to 16 at -1 goes back down to zero at 3. So you have a maximum