anonymous
  • anonymous
(Please help!) One way to describe the concentration of an acid is as a percent by volume. For example, in 40 mL of a 30% acid solution, the volume of pure acid is 40 x 30/100 or 12 mL, and the volume of water is 40-12 or 28 mL. If 5 mL of pure acid is mixed with 20 mL of water to give 25 mL of acid solution, the concentration of the solution is given by 5/25 x 100% = 20 %. If water is mixed with 50 mL of 40% acid solution, write an equation that describe the acid concentration, C(x), as a function of the volume of water added, x.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
The answer is C(x) = (20/50 + x)*100%, but why?
anonymous
  • anonymous
C(x) = [20/(x+50)] *100
anonymous
  • anonymous
yup but why though?

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anonymous
  • anonymous
50 mL of 40% acid solution contains 20mL of acid and 30mL of water, so if you add xmL of water the solution will be : (amount of acid)/(total solution)*100 amount of acid is 20mL. Total mLof solution is x+ 50mL
anonymous
  • anonymous
got it?
anonymous
  • anonymous
How did you know that the acid solution containes 20 mL of acid and 30 mL of water?
anonymous
  • anonymous
it says that is 40%. And you have 50mL. So 50*40/100 =20
anonymous
  • anonymous
what is left is water
anonymous
  • anonymous
got it?
anonymous
  • anonymous
ohh, i see.
anonymous
  • anonymous
thank you!
anonymous
  • anonymous
yw
anonymous
  • anonymous
Myko, sorry to ask you again: but how is the total mL of solution x + 50 mL? D:
anonymous
  • anonymous
x is the new water, 50 mL is 40% acid solution

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