anonymous
  • anonymous
Use the quadratic formula to solve the equation. x^2-x=-2 Please help, I dont' know why this one is so confusing to me, but I can't get it.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Callisto
  • Callisto
x^2-x=-2 x^2-x+2 =0 ax^2 +bx +c =0 \[x=(-b \pm \sqrt{b^2-4ac)}/(2a)\]
Callisto
  • Callisto
put the corresponding value to the formula
anonymous
  • anonymous
x^2-x+2=0 Use quadratic formula: ax^2-bx+2=0 a=1, b=-1, c=2

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anonymous
  • anonymous
so the x's are equal to 1 right?
Callisto
  • Callisto
since Δ<0, you will not get real solutions..
Callisto
  • Callisto
i is the imaginary number\[i=\sqrt{-1}\]
anonymous
  • anonymous
so was my answer close? I thought I was completely wrong and deleted it.
Callisto
  • Callisto
Hmm.. close but not correct... don't be afraid to make mistakes!
anonymous
  • anonymous
Sorry this is really confusing to me.
Callisto
  • Callisto
So, can you try again to get the answer?
anonymous
  • anonymous
I can try, but I don't understand still how it works. With no real numbers, it totally confuses me.
Callisto
  • Callisto
show you steps please~
anonymous
  • anonymous
trying to go over every thing you have said so far to see if I can comprehend it.
Callisto
  • Callisto
i deleted my answer.. i hope you can try...perhaps you can start with substituting the numbers into the formula and ask whatever you don't understand so we can help
anonymous
  • anonymous
I don't understand the imaginary number. Where does that come in?
anonymous
  • anonymous
what is the formula I need to use? Is it the ax^2+bx+2?
Callisto
  • Callisto
ax^2 +bx +c =0 is the general form of a quadratic equation. Before you apply the quadratic formula, you have to make the equation into general form first
Callisto
  • Callisto
then use the quadratic formula \[x=(-b \pm \sqrt{b^2-4ac)}/(2a)\]
anonymous
  • anonymous
Ok now my nerves are gone. I have gone beyond confusion now. LOL
Callisto
  • Callisto
that means you understand it now?
anonymous
  • anonymous
so when you say to put it into general form...you mean its not already in general form the way that it is?
anonymous
  • anonymous
No that means that confusion is an understatement. Now I am just plain lost!
Callisto
  • Callisto
x^2-x=-2 it is not in a general form
Callisto
  • Callisto
but when you add 2 on both sides, it is in the general form
anonymous
  • anonymous
ok
Callisto
  • Callisto
so you 'll get x^2 -x +2 =0
anonymous
  • anonymous
right ok I got that.
Callisto
  • Callisto
match the coefficient with a, b,c in the general form
Callisto
  • Callisto
a=1, b=-1, c=2
Callisto
  • Callisto
Then put these value into the quadratic formula, and you'll get x
Callisto
  • Callisto
*values
anonymous
  • anonymous
so do I really put in the numbers 1 when putting the values into the formula?
Callisto
  • Callisto
put a=1, b=-1, c=2 into the formula
anonymous
  • anonymous
ok got that...here is what it looks like; |dw:1332557688893:dw|
Callisto
  • Callisto
you missed something |dw:1332557777618:dw| Try again~
anonymous
  • anonymous
|dw:1332557813720:dw|
Callisto
  • Callisto
|dw:1332557876749:dw|
anonymous
  • anonymous
so if its not -1 then what is it? do I leave it as -b?
Callisto
  • Callisto
b=-1, -b = -(-1) =1
anonymous
  • anonymous
I am sorry. I am confused. I don't get this. Sorry for wasting your time.
anonymous
  • anonymous
negative and a negative make a positive....I see it now.
Callisto
  • Callisto
understand?
anonymous
  • anonymous
Getting there slowly. I am sorry.
anonymous
  • anonymous
Now this is what I have: |dw:1332558245309:dw|
Callisto
  • Callisto
|dw:1332558287195:dw|
anonymous
  • anonymous
thats the answer? is there more i need to do?
Callisto
  • Callisto
have you learnt imaginary number i?
anonymous
  • anonymous
Yes, but I don't get it either. Don't understand the point in it.
Callisto
  • Callisto
\[i=\sqrt{-1}\] understand?
anonymous
  • anonymous
um....yeah.
Callisto
  • Callisto
\[\sqrt{ab} = \sqrt{a}\times \sqrt{b}\]understand?
anonymous
  • anonymous
yes
Callisto
  • Callisto
\[\sqrt{-7}=\sqrt{-1\times7} =?\]
anonymous
  • anonymous
\[\sqrt{-7}i\]
Callisto
  • Callisto
nope.. slowly, use the formula above..
anonymous
  • anonymous
well -1*7=-7
Callisto
  • Callisto
Yup...\[\sqrt{-7}=\sqrt{-1\times7} = \sqrt{-1}\times \sqrt{7} \]
Callisto
  • Callisto
understand?
anonymous
  • anonymous
yes
Callisto
  • Callisto
what is the next step?
anonymous
  • anonymous
multiply the square roots?....\[\sqrt{-1}*\sqrt{7}\]
Callisto
  • Callisto
yup... then?
Callisto
  • Callisto
what is\[\sqrt{-1}\]?
anonymous
  • anonymous
i
Callisto
  • Callisto
hmm.. draw you conclusion to\[\sqrt{-7}\]
anonymous
  • anonymous
|dw:1332558977446:dw|
Callisto
  • Callisto
nope...\[\sqrt{-1\times7}=\sqrt{-1}\times \sqrt{7} =?\times \sqrt{7}\]what is that question mark ?
anonymous
  • anonymous
\[\sqrt{-7}\]
Callisto
  • Callisto
|dw:1332559217214:dw|
anonymous
  • anonymous
ok \[\sqrt{-1}=i\] I don't guess I am seeing what your getting at.
anonymous
  • anonymous
Your seriously gonna have to dummy it up a bit, b/c I really don't get this stuff very easily. I have been lucky to make it as far as I have in Algebra without totally failing.
Callisto
  • Callisto
|dw:1332559433395:dw|
anonymous
  • anonymous
Ok whew...that was frustrating, my brain hurts. So then the answer I am looking for on my problem would be....|dw:1332559544375:dw|
Callisto
  • Callisto
|dw:1332559618800:dw|
anonymous
  • anonymous
and thank you for being patient and putting up with a math illiterate student.
Callisto
  • Callisto
it'd be better if you can practise more...
anonymous
  • anonymous
Yeah this is my final exam and then I am done with math. Thank you so much for your help...i really appreciate it. REALLY!!!
Callisto
  • Callisto
yw

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