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brute force, 12?
Too many, thnk again. We always get these types of questions on tournament tests so I thought it would help to practice a few of them. I wish the others would join in.
Hint: Recall that the opposite faces of a die always add to 7.
how come they always add to 7?
@romoore93 -> I don't know.
Woah! way too many @romoore93
so they can only add up to 7 does that mean how many possibilities they are that add up to 7 from the 2?
@dpalnc --> Post the 6 you have and maybe we'll be able to get the others.
actually i didn't even realize that opposite faces sum is 7 on a standard die. wow, i learn something new everyday!
that means if wasn't standard, the answer to this question would be different then
@romoore93 --> A "die" is a single number cube, not the pair of dice.
This is a standard die --> when two adjacent sides on a standard die ...
Here are all the connections: 1-2,1-3,1-4,1-6 2-6,2-1,2-3,2-5 3-1,3-2,3-4,3-5 4-5,4-6,4-1,4-3 5-2,5-3,5-6,5-4 6-1,6-2,6-5,6-4 Unique: 1-2,1-3,1-4,1-6 2-3,2-5,2-6 3-4,3-5 4-5,4-6 Sums: 3,4,5,7 5,7,8 7,8 9,10 Unique: 3,4,5,7,8,9,10 So the answer is 7
Here's a net of a dice: http://www.aspexsoftware.com/images/dice_cube_net.jpg
Factoid unrelated to this problem: The most likely sum tossed with a pair of standard number cubes (dice) is 7.
hmm... just curious... how long do you have on a question like this in your competition?
This would be a ciphering question: 2 minutes max.
Let's write the possible sums from 1 to whatever. Can you can a sum of 1 adding the spots on two adjacent faces of the number cube?
No, there is not a face with zero on it. A sume of 1 is out. Can you can a sum of 2?
Nah.. seems that i don't know the number arrangement in a dice :(
What exactly does a standard dice look like?
This one? http://www.aspexsoftware.com/images/dice_cube_net.jpg
Standard dice: http://homepage.ntlworld.com/dice-play/DiceStandard.htm
that means actually you can add 5and 6 which gives a 11...
the minimum sum of two faces of a die is 3 (1+2) the maximum sum of two faces of a die is 11 (6+5) the sum of two adjacent faces cant be 7(it is the sum of opposite faces) so the possibilities are 3-4-5-6-8-9-10-11 so 8 possibilities
Can you not get a 6 and how do you get a 7? @ psuj
Seems like I'm not using a standard dice: http://www.aspexsoftware.com/images/dice_cube_net.jpg
Courtesy of hoblos -- This is it. the minimum sum of two faces of a die is 3 (1+2) the maximum sum of two faces of a die is 11 (6+5) the sum of two adjacent faces cant be 7(it is the sum of opposite faces) so the possibilities are 3-4-5-6-8-9-10-11 so 8 possibilities
your die is not a standard on @callisto
to become a standard one you must switch 4&5 now try
That was fun. Thanks, guys.
yeah.. thanks for the great question XD
good job ;)