the position vectors of P, Q and R are i+5j+k, -i-2j-2k and -j-k respectively. find ∠PQR.
How should i start ?
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PQ = Q-P
QR = R-Q
|PQ||QP|cos(theta) = PQ.dot.QP
Find Vector P-Q
And Vector R-Q
Find the angle by using
\[(P-Q).(R-Q)=|P-Q||R-Q| \cos \theta\]
Find theta using above. Can you do it?
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Is it PQ．RQ or QP．QR? and why?
P, Q and R are position vectors of point P, Q and R. If we want a vector directed from Q to P then it's P-Q or PQ.
and a vector directed from Q to R then it's R-Q or RQ
either choose PQ and RQ to find angle or choose QP and QR to find the angle
1)Find vector PQ and QR
2) Use vector Dot " . " product for angle,
> > PQ= -2i -7j-3k and QR= i+j+k
PQ . QR = |PQ| |QR| Cos (theta)
=> 12 = (62)^1/2 (3)^1/2 Cos (theta)
why is that when a vector is directed from Q to P, it is PQ but a vector directed from Q to R, it is RQ
technically its not 'PQ',
thing IS we'r lazy, and wont spend a sec on something that basic
Sorry, but how do I mention a person in post ? ? ?
my browser seems unresponsive . . .
i understand that QR is from Q to R (alright i can't type the arrow signs here, just assume there are arrows) but why isn't PQ from P to Q?
to mention a person in post just type @ followed by the name of that person
PQ is indeed directed from P to Q, similarly a vec. from Q to P would be QP
am i correct to do it this way? (see the attachment)