Cl2 + 2 KOH = KCl + KClO + H2O
3 KClO = 2KCl + KClO3
4 KClO3 = 3KClO4 + KCl
How much Cl2 is needed to prepare 400g of KClO4???
Ive got 38.056 gm
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
my answeris 38.056 g please verify the answer
I did not get that answer.
400 grams of KClO4 is equal to 2.89 mols.
3 KClO makes 1 KCLO3 and 4 KClO3 makes 3 KClO4.
This means you have a ratio of 4:3 for KClO3 to KClO4. Simplifying that ratio gives you 4/3:1 ratio. Now multiply 4/3 by 2.89 and that gives you the amount of KClO3 you need (in mols).
Now looking at the second equation, 3 KClO gives you only one mol of KClO3 so that means you have to multiply the amount of KClO3 you got previously by 3 to figure out how much KClO you need (once again in mols). Now Cl2 and KClO are in a 1:1 ratio so just multiply the number of mols of KClO by the molecular weight of Cl2 to get the answer.