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= 13.5

that's correct, chlorophyll!
Could you please show your work? I am having trouble getting there.

check my work again. I think my work is correct

Just exactly as the nikvist's progress!

Take derivative then plug x = 3 in!

In mean Integral!

I computed and got a negative value, which doesn't make sense :(

since when you sketch the graph, y = 3x is above y = 3x^2 - 6x

That's why you subtract: 3x - ( 3x^2 -6x)

|dw:1332618620433:dw|

Yep, then we calculate from the intersection part!

Make sense?

Next time, pls don't be hurry in make your comment that the solver is incorrect!

Since the line is above the curve in the interval [ 0, 3]

That's why you subtract: 3x - ( 3x^2 -6x) = -3x^2 + 9x

Are you with me?

I'm trying to explain as person somewhat gain more practice than the newbie!

This topic isn't as tough as you thought at all!

ok, so the formula I used is correct? (for things that only intersect twice to make one area)