A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
For the simple harmonic motion equation d=2 sin (pi/3 t), what is the maximum displacement from the equilibrium position?
is it 2?
 2 years ago
For the simple harmonic motion equation d=2 sin (pi/3 t), what is the maximum displacement from the equilibrium position? is it 2?

This Question is Closed

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1yeah...!! cause the '2' in the equation there represents the amplitude. what do you think that means?? maximum displacement from mean position! RightO!!

ggrree
 2 years ago
Best ResponseYou've already chosen the best response.0yes, it is. here's something to think about: the function sin(x) is never bigger than 1, no matter what number you choose to plug into it. therefore the maximum value of the equation d= 2sin(x) is 2.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1yes, that is the maximum value possible from that equation, since sin(any value) <= 1

Blossom_red
 2 years ago
Best ResponseYou've already chosen the best response.1The equation is d = A sin ( ωt ) ; where A is the amplitude (that is : maximum displacement from the equilibrium position) ; So d = A = 2 ( maximum displacement ) and its + or  is the position relative to equilibrium , when sin ωt = ±1 ==> t = 3( 2k+1)/ 2 , where k natural. Yes it is
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.