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SantanaG Group Title

For the simple harmonic motion equation d=2 sin (pi/3 t), what is the maximum displacement from the equilibrium position? is it 2?

  • 2 years ago
  • 2 years ago

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  1. apoorvk Group Title
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    yeah...!! cause the '2' in the equation there represents the amplitude. what do you think that means?? maximum displacement from mean position! Right-O!!

    • 2 years ago
  2. ggrree Group Title
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    yes, it is. here's something to think about: the function sin(x) is never bigger than 1, no matter what number you choose to plug into it. therefore the maximum value of the equation d= 2sin(x) is 2.

    • 2 years ago
  3. experimentX Group Title
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    yes, that is the maximum value possible from that equation, since sin(any value) <= 1

    • 2 years ago
  4. SantanaG Group Title
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    Thanks! :)

    • 2 years ago
  5. Blossom_red Group Title
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    The equation is d = A sin ( ωt ) ; where A is the amplitude (that is : maximum displacement from the equilibrium position) ; So d = A = 2 ( maximum displacement ) and its + or - is the position relative to equilibrium , when sin ωt = ±1 ==> t = 3( 2k+1)/ 2 , where k natural. Yes it is

    • 2 years ago
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