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For the simple harmonic motion equation d=2 sin (pi/3 t), what is the maximum displacement from the equilibrium position?
is it 2?
 2 years ago
 2 years ago
For the simple harmonic motion equation d=2 sin (pi/3 t), what is the maximum displacement from the equilibrium position? is it 2?
 2 years ago
 2 years ago

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apoorvkBest ResponseYou've already chosen the best response.1
yeah...!! cause the '2' in the equation there represents the amplitude. what do you think that means?? maximum displacement from mean position! RightO!!
 2 years ago

ggrreeBest ResponseYou've already chosen the best response.0
yes, it is. here's something to think about: the function sin(x) is never bigger than 1, no matter what number you choose to plug into it. therefore the maximum value of the equation d= 2sin(x) is 2.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.1
yes, that is the maximum value possible from that equation, since sin(any value) <= 1
 2 years ago

Blossom_redBest ResponseYou've already chosen the best response.1
The equation is d = A sin ( ωt ) ; where A is the amplitude (that is : maximum displacement from the equilibrium position) ; So d = A = 2 ( maximum displacement ) and its + or  is the position relative to equilibrium , when sin ωt = ±1 ==> t = 3( 2k+1)/ 2 , where k natural. Yes it is
 2 years ago
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