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anonymous
 4 years ago
For the simple harmonic motion equation d=2 sin (pi/3 t), what is the maximum displacement from the equilibrium position?
is it 2?
anonymous
 4 years ago
For the simple harmonic motion equation d=2 sin (pi/3 t), what is the maximum displacement from the equilibrium position? is it 2?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah...!! cause the '2' in the equation there represents the amplitude. what do you think that means?? maximum displacement from mean position! RightO!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, it is. here's something to think about: the function sin(x) is never bigger than 1, no matter what number you choose to plug into it. therefore the maximum value of the equation d= 2sin(x) is 2.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1yes, that is the maximum value possible from that equation, since sin(any value) <= 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The equation is d = A sin ( ωt ) ; where A is the amplitude (that is : maximum displacement from the equilibrium position) ; So d = A = 2 ( maximum displacement ) and its + or  is the position relative to equilibrium , when sin ωt = ±1 ==> t = 3( 2k+1)/ 2 , where k natural. Yes it is
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