anonymous
  • anonymous
1000e^.03= 2000
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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apoorvk
  • apoorvk
i guess 'e' isnt that constant with value 2.71 in here.. so.. take 1000 to rhs and divide 2000. next take log. and get the answer, which you post and verify!
jim_thompson5910
  • jim_thompson5910
You're missing a variable somewhere...
anonymous
  • anonymous
where at?

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jim_thompson5910
  • jim_thompson5910
where is 'x'?
anonymous
  • anonymous
and e is the constant value of 2.71.
jim_thompson5910
  • jim_thompson5910
yes i know, e is not the variable
anonymous
  • anonymous
its solving for how long it takes 1000 to double at a constant rate of 3%
jim_thompson5910
  • jim_thompson5910
y = P*e^(0.03t) 2000 = 1000*e^(0.03t) 2000/1000 = e^(0.03t) 2 = e^(0.03t) ln(2) = 0.03t ln(2)/0.03 = t 23.1049 = t t = 23.1049 So it will take approximately 23.1049 years

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