can anyone help me with right angle trigonometry?

- anonymous

can anyone help me with right angle trigonometry?

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- schrodinger

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- anonymous

What help do you need?

- anonymous

explanation of how to do it. i can post a few problems if need be?

- anonymous

Yeah It's a good a idea you to post an specific problem.

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## More answers

- anonymous

ok just give me a few to put it up

- anonymous

ok, take your time

- anonymous

|dw:1332624251881:dw|
1. Calculate GH.
2. Calculate EG.
3. Calculate GF.

- anonymous

i cannot contact my professor so i dont understand this very well

- anonymous

I suposse EH = 5 and HF = 28.2. Am I right?

- anonymous

HF= 28.8

- anonymous

sorry I typo =P

- anonymous

its ok

- anonymous

Ok. Give a second

- anonymous

ok

- anonymous

Ok, It could help you know that \[\angle HGF =\angle HFG\]

- anonymous

yes that helps but very little

- anonymous

Ok it that is the case then. \[\frac{5}{GH}=\frac{GH}{28.8}\]

- anonymous

You can solve for GH.

- anonymous

cross multiply right?

- anonymous

yeah

- anonymous

Once you get the value of GH you can use Phytagorean theoremn to find GF

- anonymous

and use it again to find the last unknow.

- anonymous

so it would be GH squared= 144 and then i square root it?

- anonymous

yeah and you'll get GH = 12

- anonymous

yeah thats what i got

- anonymous

Good job!

- anonymous

thanks now how do i do this for #2?

- anonymous

I need to go now. I'll be back soon I hope I was useful to you.

- anonymous

i still need help.....

- anonymous

Try to use the theorem I told you to use. If you get stucked you can ask for help on the chat or wait. I won't be out for too long.

- anonymous

chat?

- anonymous

The little square that says mathematics just below this thread

- anonymous

i got it. thanks

- anonymous

You're welcome =)

- saifoo.khan

where are u stuck?

- anonymous

on number 2

- anonymous

bc idk what the pathagryen theorem is

- saifoo.khan

http://www.youtube.com/watch?v=s9t7rNhaBp8

- saifoo.khan

http://www.youtube.com/watch?v=nMhJLn5ives

- anonymous

i still donot understand very much of this

- apoorvk

okay nikki. just a minute. i think we ned to start from the beginning okay?

- anonymous

ok well i understand #1 but i dont see how to do #2

- apoorvk

hmm okay. you are comfortable with pythagoras theorem right? in that figure, in triangle EGH, angleEHG is right angle. you understand right? and EH=5 is given. do i understand it right?

- anonymous

yes... but in the pythagorean theorem it doesnt tell me how to do the necessary steps for #2

- apoorvk

okay, in right triangle EGH right angled at H, can you feel that
EH^2 + HG^2 = GH^2
you figure that out?

- anonymous

yes i figured that already

- anonymous

and i would follow what steps to find HG?

- apoorvk

yeah exactly. you found out GH in #1 right? so just plug in th evalues. and then solve like you confirmed earlier. c'mon have some confidence in yourself?

- apoorvk

you found out GH in #1 right?

- anonymous

i dont understand how to find HG tho

- anonymous

I think you mean EG^2 apporvk

- anonymous

You already find HG nikki

- anonymous

do i use a^2+b^2=c^2

- apoorvk

i thought you said you knew #1. anyways. actually the diagram isnt totally visible so i ll draw one and you edit it (reply using diagram option) and write the missing part.
yeah exactly!!!

- anonymous

yes nikki

- anonymous

i meant EG not HG

- anonymous

You know the values of EH and HG, so just plug them in this equation: EH^2 +HG^2 = EG^2

- anonymous

and solve for EG.

- anonymous

and i dont know GF so i cannot do that equation

- anonymous

but i'll try

- anonymous

You can, there is no GF on that equation

- anonymous

oh my bad, i meant to type so 169=EG^2

- anonymous

that right, good job!

- anonymous

so EG=13?

- anonymous

yes.

- anonymous

ok now how do i find GF?

- anonymous

Now you can do the same for the triangle FHG

- anonymous

You know the value of FH and HG.

- anonymous

ok

- apoorvk

nikki i see where the problem is. try not to look at the bigger picture, and just a consider one right triangle at a time. find any two sides somehow to calculate the third. now that third side can be a part of another right triangle, so consider that triangle now and get the missing data in that or whatever the question asks. its simple. relax and cool down. i guess you are worrying too much. (drink some water) :))

- anonymous

so the equation would read as?

- anonymous

You tell me. Don't worry if its wrong.

- anonymous

FH^2+ HG^2= GF^2?

- anonymous

yeah! you're totally right! =)

- anonymous

cool :) i feal somewhat smarter now

- anonymous

I'm glad to hear that. Have a nice day!

- anonymous

GF = 31.2 right?

- anonymous

yes, I got the same result.

- anonymous

sweet :)

- anonymous

:)

- anonymous

|dw:1332628673814:dw|
1.Calculate NL.
2.Calculate KN.
3.Calculate MN.

- anonymous

so to find nl do i follow the same steps i did for the last 3 questions?

- anonymous

Wait a second.

- anonymous

The problem is similar but the steps toward the solution are a little different.

- anonymous

ok. i have to go for a bit i will be on later can you help then?

- anonymous

yeah. Just message me.

- anonymous

ok thx bye

- anonymous

bye!

- anonymous

back on now......

- anonymous

Ok. Lets find NL.

- anonymous

Any idea?

- anonymous

ok lets find NL :)

- anonymous

HELPPPPPPPPPP!!!!!!!!!!!!!!!!!

- anonymous

Hi

- anonymous

Any idea nikki?

- anonymous

no i dont

- anonymous

Look at the triangle KLN. You'll notice that it is a right triangle, so you can use the pythagorean theorem on it. You already know the length of two of it's sides. KN = 26 and KL = 24.

- anonymous

so those are sides a and c?

- anonymous

yes.

- anonymous

ok so how would i find b?

- anonymous

You should get an equation like this: \[KN^2+NL^2=KL^2\]

- anonymous

yeah

- anonymous

You know the values of KL and KN, so just solve for NL.

- anonymous

kn= 576 and kl=676

- anonymous

Ohh I thought KN = 26

- anonymous

and KL = 24

- anonymous

KM=26 ML=10 KL=24

- anonymous

so i messed up up there sorry

- anonymous

Don't worry. The important thing is that you understand how to apply trigonometry.

- anonymous

yeah sure

- anonymous

Wait, I think those lengths are wrong.

- anonymous

no their right, their the lengths given on the actual worksheet.

- anonymous

Well you can't draw a right triangle with those lenghts. Look carefully and you'll realize that if the angle KNL is a right angle, then lenght KL must be greater than KN.

- anonymous

Maybe KM = 26

- anonymous

KM=26

- anonymous

Ok then =)

- anonymous

yeah

- anonymous

Well again it's useful to know that \[\angle NKL = \angle NLM\]

- anonymous

yep i got that already :P

- anonymous

So you can relate the sin of both angles.

- anonymous

sin?

- anonymous

sorry, i meant cos!

- anonymous

oh ok

- anonymous

the cosine of both angles.

- anonymous

\[\frac{KL}{KM}=\frac{NL}{ML}\]

- anonymous

ok so do i cross multiply?

- anonymous

I'm not sure what you mean by "cross multiply". But if you multiply both sides of the equation by ML you'll get the value of NL

- anonymous

how do you do that?

- anonymous

\[ML\cdot \frac{KL}{KM}=\frac{NL}{ML}\cdot ML \]

- anonymous

i dont understand

- anonymous

So \[NL=ML\cdot \frac{KL}{KM}\]

- anonymous

oh

- anonymous

Ok do you have a clear understanding where this equation come from?\[\frac{KL}{KM}=\frac{NL}{ML}\]

- apoorvk

still in trouble nikki? i guess no-data is responding with a lot of patience

- anonymous

yes

- anonymous

yes

- anonymous

Ok. We know the values of KL = 24, KM = 26 and ML = 10

- anonymous

so it would be NL=10*24/26?

- anonymous

You can plug them into the equation, so you'll get something like this: \[\frac{24}{26}=\frac{NL}{10}\]

- anonymous

Yes!!!

- anonymous

Now you got NL

- anonymous

so i get 9.230769231?

- anonymous

Now you can apply the same procedure to find NM but this time with the triangle NLM.Do you feel confident enough to do it by yourself?

- anonymous

yes. But it's better leave it as 120/13, because you'll need that value later.

- anonymous

no i do not

- anonymous

Ok. The triangle LNM has 3 sides. NL, NM and ML.

- anonymous

What theorem relates these sides?

- anonymous

idk

- anonymous

It's the same theorem we used before.

- anonymous

something like a^2 + b^2 = c^2

- anonymous

oh my bad thats what i thought

- anonymous

It's great you thought it. Don't be afraid to be wrong nikki =P

- anonymous

Can you set up the equation with the sides that we have?

- anonymous

yes i think i can

- anonymous

Ok what you got?

- anonymous

waht am i trying to to find?

- anonymous

You need to find the length NM. You already know that ML = 10 and NL = 120/13

- anonymous

ok so is NM the hypotenuse?

- anonymous

NO, remember that the hypotenuse is the side opposite to the right angle.

- anonymous

In this case the right angle is\[ \angle LNM\]

- anonymous

yes i know i just cant find the diagram

- anonymous

Ok. |dw:1332639117378:dw|

- anonymous

Does that help =)?

- anonymous

yes :)

- anonymous

so i need to find NM?

- anonymous

Yes, and what is the hipotenuse?

- anonymous

ML

- anonymous

yeah! You're right. and the equation is?

- anonymous

not entirely sure but ML=c^2 and NM=a^2 and NL=b^2

- anonymous

You're close just drop the square. So ML = c, NM = a and NL = b

- anonymous

and you get something like this\[ML^2=NM^2+NL^2\]

- anonymous

yeah

- anonymous

plug in the values of ML and NL and solve for NM.

- anonymous

10 and 120/13

- anonymous

so squared that would be 100 and idk the other one

- anonymous

\[10^2=NM^2+\left(\frac{120}{13}\right)^2\]

- anonymous

ok?

- anonymous

yes, you're right, now just solve for NM

- anonymous

85.20710059 for nl so nm= 14.79289941

- anonymous

right?

- anonymous

You had get 9.2 for NL before, maybe you made a little mistake.

- anonymous

idk

- anonymous

which one is it?

- anonymous

NL = 120/13 = 9.2

- anonymous

yeah then squared it would bebe 84.64

- anonymous

so NM=15.36

- anonymous

I got this: \[NM^2=10^2-9.2^2\]

- anonymous

so NM = 3.8

- anonymous

hmm ok

- anonymous

Is it clear? If you're unsure feel free to ask.

- anonymous

thanks for your help... its clear. If i have any trouble w/anything else i will ask you :) :)

- anonymous

Ok =). Have a nice night then !

- anonymous

you too :)

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