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Must be 6X
factor the numerator and denominator: [(2x-3)*(x+4)] / [x*(x-4)] ....hmm nothing cancels... btw, what do you want done here?
It is 6x
i think he needs to solve for x. move the denominator to the other side of the equation, then start solving by using algebra. The rule to remember when dealing with < or > signs is to FLIP THE SIGN each time you are multiplying or dividing by a negative number.
yea it is solving for x. although i got to the factoring but i was unsure of what to do next
ok, then we need to solve, that is, find all the x-values that will make the stament true...
so after multiplying and doing algebra, you should have x^2 +9x + - 12 <0
from the factored expression [(2x-3)*(x+4)] / [x*(x-4)] find all x values that will make the numerator = 0 then all x values that will make the denominator = 0
for numerator: x = 3/2, -4 for denominator: x = 0, 4 now pick values within those interval and check what will make f positive or negative: |dw:1332627744298:dw|
hello? not here anymore...
trying to figure this out... this is confusing me
are u there?
yea.. i dont get it still
do you understand how I factored to get the new expression: [(2x-3)*(x+4)] / [x*(x-4)] < 0
ok, do you understand @kumar2006 answers? where do you think he got those numbers?
oh, isee. is that the final answer?
kumar2006 answers are correct. but do you see how he got those solution sets?
yes, final answer.
alright i get it now, thanks