does anyone one know how to do the Solve for x: x + 4 < 2 I need some help please
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You would add -2 to both sides... 5x > -10
Then you would divide both sides by 5.... x > -2
kell1170 how would i set that up ?
can you help me with these last few please i only have this one -4x + 3 < 15
and two more please
Whoops didn't show my work. Sorry. Okay you have 5x - 2 > -12. So you take and add 2 both sides +2 +2
Then you just have 5x > -10 so you divide both sides by 5 to get x by itself. x > -2
Your next one is -4x+3>15 You subtract 3 from each side
Then you have -4x > 12. Now divide by -4 each side
the next two are 7(x – 1) > -14 and the last one is -4(x – 2) < 2 ( x + 1)
7(x-1) > -14. First, you multiply everything in the parenthesis by 7. You now have 7x-7 > -14. Then, add 7 to both sides.
Now you have 7x > -7. Now divide both sides by 7 to get x by itself. x> -1
Your last one is -4(x-2) < 2(x+1). You distribute the numbers to everything in the parenthesis and you now have
-4x+8 < 2x+2 (Remember two negatives=a positive always)
Now, you can do this two different ways, but I'm gonna show you the way I would do it. I would add -4x to each side. You now have
8 < 6x+2 so you subtract 2 from each side
and you have
6 < 6x so you divide each side by 6 to get X by itself and you end up with
1 < x
I have a question did i do this one right ? x + 4 < 2 x>-4