The one to one function f is defined by:
Find the inverse of f. Then, give the domain and range of f^-1 using interval notation.
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for finding inverse of a function y=f(x) you need to write x in terms of y (rearrange the equation), then interchange y and x. that ll be f inverse of x. hope this helps. post what you think should be the answer.
That's the problem though, I don't know how to switch the equation
okay i ll show you below. uh-oh. do you mean f=x/(7x+2) up there?
if yes then,
(hmm tricky one. you hafta use hook or crook to get it)
nope now you can carry on further. :))
and domain and range a problem?
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is the inverse 2x/1-7x
exactly!!!!! but use brackets when quoting equations here so that we can understand better. :)
okay, umm.. the domain..
umm.. you mean 1/7 instead of -2/7 over there in domain? cause at 1/7 the denominator is 0, and the function value shoots up to infinity, and so gets undefined.
what you posted as range would be the domain.
so the domain is: (-inf,1/7)U(1/7,inf)?
then whats the range cause thats what i put for the range?
yeah thats domain. (i hope you know what domain and range are basically).
now for range let me work that out its a bit complex here.
i know what they are, math isnt my greatest subject lol!
range should be.. umm...'cause the graph will be like:
sorry i got really puzzled in between so took me some time.
yeah so what you posted as domain should be the range!!! basically interchange them!