anonymous
  • anonymous
What is the coefficient in fron of the"x"^2 when (2x+3)^4 is expanded?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
How did you get this?
anonymous
  • anonymous
do you just leave the 3 out of it?
anonymous
  • anonymous
i used Pascal's triangle: (a + b)^2 = 1 2 1 (a + b)^3 = 1 3 3 1 (a + b)^4 = 1 4 6 4 1 the right side of the equal signs are just the coefficients of the binomials expanded.

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anonymous
  • anonymous
sorry, I misread your question. I thought your were looking for the coefficient of the leading term. you want the coefficient of the x^2 term right?
anonymous
  • anonymous
Yes, the coefficient if front of x^2.
anonymous
  • anonymous
ok, so... you see the 6 in the (a + b)^4?
anonymous
  • anonymous
yes
anonymous
  • anonymous
that's the term 6a^2b^2. since your a=2x, b=3 6*(2x)^2*(3)^2 = 6*4x^2*9 = 6*4*9*x^2 = 216x^2 your coefficient for the x^2 term is 216
anonymous
  • anonymous
still faster than if you were to multiply the whole thing out...
anonymous
  • anonymous
SO is that the answer because it says the coeficcient in front of x^2
anonymous
  • anonymous
SO is that the answer because it says the coeficcient in front of x^2
anonymous
  • anonymous
yes...http://www.wolframalpha.com/input/?i=expand+%282*x%2B3%29%5E4
anonymous
  • anonymous
Okay thank you so much for your help!
anonymous
  • anonymous
np

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