anonymous
  • anonymous
In this problem, what are the steps I need to use? Please help. (8x+5)(2x^2+9x+5)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
(8x+5)(2x^2+9x+5)= 18x^3+72x^2+40x+10x^2+45x+25= 18x^3+82x^2+85x+25
anonymous
  • anonymous
are these the steps I need to take? or is it the answer?
myininaya
  • myininaya
\[(8x+5)(2x^2+9x+5)=8x(2x^2+9x+5)+5(2x^2+9x+5)\]

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More answers

myininaya
  • myininaya
\[=8x(2x^2)+8x(9x)+8x(5)+5(2x^2)+5(9x)+5(5)\]
myininaya
  • myininaya
Do you see what I did so far?
anonymous
  • anonymous
I do.
myininaya
  • myininaya
Great! Now it is just matter of using law of exponents and the fact that multiplication is commutative
anonymous
  • anonymous
Yes. It is the answer
myininaya
  • myininaya
and also associative \[=8(2)x(x^2)+8(9)x(x)+8(5)x+6(2)x^2+5(9)(x)+5(5)\]
anonymous
  • anonymous
oh ok...
myininaya
  • myininaya
\[=16x^{2+1}+72x^{1+1}+40x+12x^2+45x+25\]
anonymous
  • anonymous
Oh wow, that last one looks confusing.
myininaya
  • myininaya
You don't have to do that step I was just trying to use some basic rules
myininaya
  • myininaya
\[=16x^3+72x^2+40x+12x^2+45x+25\] Combine like terms and you will be done
myininaya
  • myininaya
But if you need me to go over that step with you again I will
myininaya
  • myininaya
\[=8x(2x^2)+8x(9x)+8x(5)+5(2x^2)+5(9x)+5(5) \] This was the expression I had before I made it confusing for you I think right?
anonymous
  • anonymous
so we are combining like terms for the last step?
myininaya
  • myininaya
Yes! :)
anonymous
  • anonymous
Yes that was before it got confusing.
anonymous
  • anonymous
Ok so let me give this a shot then.
myininaya
  • myininaya
Ok...I will give you some time to yourself and say something when you want me to come back k?
anonymous
  • anonymous
which one are we combining like terms for so I can make sure I have the right one wrote down.
myininaya
  • myininaya
\[=16x^3+72x^2+40x+12x^2+45x+25 \]
anonymous
  • anonymous
Ok i had the wrong one...give me a minute let me see what I get..
anonymous
  • anonymous
I am not so sure I got it right, but here is what I got. 185x^9+25
myininaya
  • myininaya
Oh no that is not right
anonymous
  • anonymous
Ok I didn't think so. I am not good at this stuff...
myininaya
  • myininaya
like terms are terms with the same variable part
anonymous
  • anonymous
Ok by variable you mean the "x" right?
myininaya
  • myininaya
You want to look for all the terms with x^3 (and add those together) Then you want to look for all terms with x^2 (and add those together) Then you want to look for all terms with x (and add those together) And add any constant terms that are remaining together
anonymous
  • anonymous
Oh oK...trying again.
myininaya
  • myininaya
Ok go you! You can do it! :)
anonymous
  • anonymous
Ok trying again.
anonymous
  • anonymous
16x^3+84x^2+85x+25
myininaya
  • myininaya
+10000 points :) Good job!
anonymous
  • anonymous
THANK YOU for showing me how to work it out!!!!!
myininaya
  • myininaya
But wait
myininaya
  • myininaya
I think I made a typing error above k?
anonymous
  • anonymous
ok...
myininaya
  • myininaya
\[=8x(2x^2)+8x(9x)+8x(5)+5(2x^2)+5(9x)+5(5) \] We had this and I accidentally wrote \[=8(2)x(x^2)+8(9)x(x)+8(5)x+6(2)x^2+5(9)(x)+5(5) \] See how that one number changed from a 5 to a 6 my bad :(
myininaya
  • myininaya
\[=16x^3+72x^2+40x+10x^2+45x+25\]
anonymous
  • anonymous
Ok so need to try it again right? will make the answer different.
myininaya
  • myininaya
yes it will and sorry about that
anonymous
  • anonymous
Not a problem it happens. I got 16x^3+82x^2+85x+25
myininaya
  • myininaya
Bingo! Now you can take the points and be happy. lol
anonymous
  • anonymous
Thank You so much! Your a lot more patient than some of these people on here, and I like being showed how its worked out and not having the answer just given to me! Thanks again!!
myininaya
  • myininaya
You are totally welcome! :) I like people who want to learn the material so you are really awesome! Go you! Have a good night!
anonymous
  • anonymous
You too!

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