find the equation of the line tangent to the graph of y=3x-cosx at x=0.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Take the derivative, evaluate at zero. Use that value as the slope that goes through the point of the function at zero.
Not the answer you are looking for? Search for more explanations.
yeah, evaluate at x=0.
hmm i got derivative = 3+sinx
What is sin(0)?
why dont u evalute 0 at cosx? isnt that the original equation
I made a mistake above. The derivative evaluates to three at x=0, and the function evaluates to -1 at x=0. So, the tangent line is y=3x -1
oh that is one of my answer choices
still slightly confused so u plugged in zero to the derivative and the original function?
OK, summary: The derivative at the value of x finds the slope of the tangent line. The function at the value of x gives the point the tangent line goes through. Combine these two facts to get the equation of the tangent line.