anonymous
  • anonymous
find the equation of the line tangent to the graph of y=3x-cosx at x=0.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Take the derivative, evaluate at zero. Use that value as the slope that goes through the point of the function at zero.
anonymous
  • anonymous
ooh thanks
anonymous
  • anonymous
well what i got is derivative is 3+sinx?

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anonymous
  • anonymous
yeah, evaluate at x=0.
anonymous
  • anonymous
hmm i got derivative = 3+sinx
anonymous
  • anonymous
What is sin(0)?
anonymous
  • anonymous
why dont u evalute 0 at cosx? isnt that the original equation
anonymous
  • anonymous
I made a mistake above. The derivative evaluates to three at x=0, and the function evaluates to -1 at x=0. So, the tangent line is y=3x -1
anonymous
  • anonymous
oh that is one of my answer choices
anonymous
  • anonymous
still slightly confused so u plugged in zero to the derivative and the original function?
anonymous
  • anonymous
OK, summary: The derivative at the value of x finds the slope of the tangent line. The function at the value of x gives the point the tangent line goes through. Combine these two facts to get the equation of the tangent line.
anonymous
  • anonymous
ook thanks so much
anonymous
  • anonymous
No sweat.

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