anonymous
  • anonymous
In the reaction 2Al + 3 MnO ---> Al2O3 +3Mn 220g Al and 400g of MnO are mixed, which substance is remained in access after the reaction and by how much \? Ive got that Al will remain at the en by 4.32g
Chemistry
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
at the end of the question after 4.32 its Moles not gram please check my answer
anonymous
  • anonymous
Mn will remain in exces as it is 5.7mol and Al2O3 is 1.90 moles so we can say mn will be in excess by 3.8 ok
anonymous
  • anonymous
but here MnO is the limitng reagent naa ???

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anonymous
  • anonymous
ha and they are asking which remain not which get consume :P
anonymous
  • anonymous
how can u say that Al2O3 is 1.9 mole
anonymous
  • anonymous
cal krk :P
anonymous
  • anonymous
arre haan wo to theek hai 3--->1 => 5.6 ---> 5.6/3 = 1.89
anonymous
  • anonymous
look u find limiting reagent is MNO ok now u see its coefficeint is 3 ant its mole is 5.7 now cal that AL2O3 coefficeint is 1 so its mole is 1.90 now u see for Mn in a same way and u find coeffiecint is same dat is 3 means its mole is 5.7 now u see that no. of mole of Mn is max dan Al2O3
anonymous
  • anonymous
whose mole max means excess amount :) and by how much jusst subtract the value :)
anonymous
  • anonymous
now for 1 Al2O3 -- 2 Al ==> 1.9 Al2O3-- 3.8 Al now left is 8.14-3.8= 4.32
anonymous
  • anonymous
ye mera DIMAAAG hai
anonymous
  • anonymous
arrey limiting reaent is MnO so y u touch Al
anonymous
  • anonymous
OHHHOOOO maine question hi galat samajh liya tha ek baat batao Al kitna use hua main sirf reactants dekh rha th jabki last me product bhi to hai hmmmmm....got it
anonymous
  • anonymous
dekho Al k mole 8.4 h and MnO k 5.7 now u see MnO is limiting reagent here means 5.7 mole i used from both of the reactantss ok u knw VJ sir k chem he is awesome** :)

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