anonymous
  • anonymous
A cat is able to land on its feet after a fall,taking the advantage of the principle of conservation of angular momentum.Explain how ?
Physics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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NotTim
  • NotTim
Well, momentum is p=mv....
NotTim
  • NotTim
Maybe since d=vt, the cat is somehow decreasing the distance or time by falling a special way?
NotTim
  • NotTim
p=m(d/t) or... p=(F/a)(d/t)

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NotTim
  • NotTim
if you think f=ma. I'm using super simple physics right now...
Mani_Jha
  • Mani_Jha
A cat stretches its body, increasing its moment of inertia. As the moment of inertia, the angular velocity decreases.(L=Iw is constant) So, the cat turns slowly, and can easily turn over and land on its feet. If however the turn is faster, the cat may have a higher chance of falling on its back than on its feet.
anonymous
  • anonymous
yes wat manijha says is perfectly correct but do remeber that as he says this is possible only on the assumption that there isnt much of a height to which the cat leaps(as gravity creates a torque on the cat as it is an extended body and angular momentum is conserved only when there is no net torque on the system)

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