A cat is able to land on its feet after a fall,taking the advantage of the principle of conservation of angular momentum.Explain how ?
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Well, momentum is p=mv....
Maybe since d=vt, the cat is somehow decreasing the distance or time by falling a special way?
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if you think f=ma. I'm using super simple physics right now...
A cat stretches its body, increasing its moment of inertia. As the moment of inertia, the angular velocity decreases.(L=Iw is constant) So, the cat turns slowly, and can easily turn over and land on its feet. If however the turn is faster, the cat may have a higher chance of falling on its back than on its feet.
yes wat manijha says is perfectly correct
but do remeber that as he says this is possible only on the assumption that there isnt much of a height to which the cat leaps(as gravity creates a torque on the cat as it is an extended body and angular momentum is conserved only when there is no net torque on the system)