Hard Problem**
Double Integral
volume of tetrahedron bounded by
4x+4y+7z=112
x=15y
x=0
z=0

Hard Problem**
Double Integral
volume of tetrahedron bounded by
4x+4y+7z=112
x=15y
x=0
z=0

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k so i have the plane's intercepts at y = -16, x=-26, and z = -16

not exactly sure how to set up the limits of integration

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