anonymous
  • anonymous
For the following function f(x) =2x^2-3x-9/x^2-2x-3. Find the vertical, horizontal and oblique asymptote and hole in the graph (if any). Show all steps.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
NotTim
  • NotTim
You MUST have a note on this.
NotTim
  • NotTim
To find the...asymptote of something sub infinity in for x (that's not a joke; that's for eitehr vertical or horizontal; pretty sure horizontal)
NotTim
  • NotTim
Since oblique is just a line...

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

NotTim
  • NotTim
diagonal one..
anonymous
  • anonymous
Okay.. can you be more specific please?
NotTim
  • NotTim
I just don't know. That's the truth. I was hoping that maybe you had a textbook or note for this.
NotTim
  • NotTim
I remember another required some table of values, maybe vertical asymptote.
NotTim
  • NotTim
i...just cant remember. I suggest trying Khan Academy or just using google to look up the meethods...
NotTim
  • NotTim
If you really don't have a textbook or note on this.
NotTim
  • NotTim
hey?
anonymous
  • anonymous
Okay, i'm checking. Thank you.
NotTim
  • NotTim
yeah. sorry that I cant tell you directly; but I haven't memorized the info myself.
campbell_st
  • campbell_st
factorising \[((2x +3)(x -3))/(x+1)(x-3)\] gives \[(2x+3)/(x+1)\] a vertical asymptote exists at x = -1 a point of discontinuity exists at x =3, you can find the y value for the ordered pair this is because the original equation before simplifying has the restriction \[x \neq 3\] use synthetic or polynomial division to find the oblique(horizontal) asymptote it exists at y = 2
anonymous
  • anonymous
since the factor of (x - 3) cancelled, that is where you have a hole in your graph. It is a point of discontinuity... removable one at that.

Looking for something else?

Not the answer you are looking for? Search for more explanations.