For the following function f(x) =2x^2-3x-9/x^2-2x-3. Find the vertical, horizontal and oblique asymptote and hole in the graph (if any). Show all steps.
Stacey Warren - Expert brainly.com
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You MUST have a note on this.
To find the...asymptote of something sub infinity in for x (that's not a joke; that's for eitehr vertical or horizontal; pretty sure horizontal)
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Okay.. can you be more specific please?
I just don't know. That's the truth. I was hoping that maybe you had a textbook or note for this.
I remember another required some table of values, maybe vertical asymptote.
i...just cant remember. I suggest trying Khan Academy or just using google to look up the meethods...
If you really don't have a textbook or note on this.
Okay, i'm checking. Thank you.
yeah. sorry that I cant tell you directly; but I haven't memorized the info myself.
\[((2x +3)(x -3))/(x+1)(x-3)\]
a vertical asymptote exists at x = -1
a point of discontinuity exists at x =3, you can find the y value for the ordered pair
this is because the original equation before simplifying has the restriction
\[x \neq 3\]
use synthetic or polynomial division to find the oblique(horizontal) asymptote
it exists at y = 2
since the factor of (x - 3) cancelled, that is where you have a hole in your graph. It is a point of discontinuity... removable one at that.