anonymous
  • anonymous
A curve y=3 sqrt x and the line y=x interesct at O and P. Find the area of the shaded region which lies between the curve and the line.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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lgbasallote
  • lgbasallote
de ja vu
lgbasallote
  • lgbasallote
oh it's area now..
anonymous
  • anonymous
\[\int _0^9 3\sqrt{x} - \int_0^9 xdx \] *fingers crossed*

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More answers

anonymous
  • anonymous
|dw:1332669981371:dw|
Callisto
  • Callisto
\[\int\limits_{0}^{9} 3\sqrt{x} -x dx\]
anonymous
  • anonymous
Yay!
anonymous
  • anonymous
So, how? You integrate and then?
anonymous
  • anonymous
Why -x?
anonymous
  • anonymous
Think!
anonymous
  • anonymous
because it's the equation of the line? or what? I'm confused.
Callisto
  • Callisto
the upper area - lower area..
anonymous
  • anonymous
Yes, but the second line isn't a curve... so why would you integrate it?
Callisto
  • Callisto
1 Attachment
Callisto
  • Callisto
just like doing the normal integration..
anonymous
  • anonymous
Yes, I know how to integrate it, but why would you add the -x?
Callisto
  • Callisto
actually it is not add.. but less x :P
anonymous
  • anonymous
Oh, OK, but still, why would you minus the x?
Callisto
  • Callisto
when you integrate the curve, you'll get all area under the curve.. But that's not what you want .. you don't want the area under the straight line, right?
anonymous
  • anonymous
No, I don't.... But why would you integrate a straight line?
Callisto
  • Callisto
So you do the integration again for the straight line to get the area under the straight line
Callisto
  • Callisto
that is|dw:1332670634664:dw|
anonymous
  • anonymous
Would the answer be 27/2?
Callisto
  • Callisto
So to get the area you want , you just need to use the area under the curve - area under the straight line
anonymous
  • anonymous
That makes more sense :) So, would the answer be 27/2?
Callisto
  • Callisto
i think so... Originally, it also makes sense :P
anonymous
  • anonymous
Haha, true... Can you check for me.. because sometimes I'm sloppy with calculation.
Callisto
  • Callisto
i also get 27/2 :)
anonymous
  • anonymous
Great :)

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