anonymous
  • anonymous
How about this... \frac {3}{3+\frac {3}{3+\frac {3}{3+\frac {3}{...}}}}
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\frac {3}{3+\frac {3}{3+\frac {3}{3+\frac {3}{...}}}}\]
anonymous
  • anonymous
x^2 + 3x = 3
lgbasallote
  • lgbasallote
let x equal that 3/3+x = x 3 = 3x + x^2 x^2 + 3x - 3 =0 -3 +/- sqrt (9 - 4(1)(-3)/2(1) -3 +/- sqrt (9 + 12) /2 -3 +/- sqrt 21/2 x= 0.7913

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lgbasallote
  • lgbasallote
there seems to be something wrong with my quadratic formula... x^2 + 3x = 3 x(x+3) = 3 x = 3 x = 0 ???
anonymous
  • anonymous
if x=3, isnt the rhs=18? @Igbasallote
anonymous
  • anonymous
and if x=0, rhs=0
lgbasallote
  • lgbasallote
oh yeah...so my quadratic formula is right...my factor was the one that's wrong =))))))
apoorvk
  • apoorvk
|dw:1332670830662:dw| simplify and enjoy!!!
Callisto
  • Callisto
Sorry to ask, how can you guys get to this step: 3/3+x = x ?
apoorvk
  • apoorvk
callisto, i hope you can see that first the whole expression's value to be 'x'. then the part in denominator after "3+.." that is just 'x' as well too right?? because the whole equation continues to divided infinite times!!!
Callisto
  • Callisto
you let it be x , so it is x...
Callisto
  • Callisto
Nah.. it seems i understand a little..

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