2bornot2b
  • 2bornot2b
Show that an integer of the form 6k+5 is also of the form 3k+2, but not conversely
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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2bornot2b
  • 2bornot2b
I think I can work on the first part, but have no idea on the second "converse part'
Mani_Jha
  • Mani_Jha
Can you show your work on the first part?
2bornot2b
  • 2bornot2b
So if an integer is of the form 6k+5, then it is equivalent to 6k+3+2, which is equal to 3(2k+1)+2. Now if k is an integer 2k+1 is also an integer, so it is of the form 3k+2

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2bornot2b
  • 2bornot2b
I am sorry, I should have mentioned k is an integer.
Mani_Jha
  • Mani_Jha
Yes, then just try the reverse. 3k+2=6k+5-3k-3 =6k-3(k+1)+5 6{k-(k+1)/2}+5 =6(k-1)/2+5 (k-1)/2 may not be an integer if n is even. See that the expression does not come out to be in the form 6n+5, where n is an integer. So the converse is true sometimes, but not always.
Mani_Jha
  • Mani_Jha
Ok?
Zarkon
  • Zarkon
for the converse...just give a specific counter example
Zarkon
  • Zarkon
2=3*0+2 2=6k+5 -3=6k k=-1/2 which is not an integer

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