anonymous
  • anonymous
Michael rolled two number cubes, numbered 1 to 6, simultaneously. According to theoretical probability, how many of the rolls should Michael expect the sum to be 6 if he rolled them 108 times?
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
sorry i suck at probability!
anonymous
  • anonymous
me too:(
anonymous
  • anonymous
do you think i would divide 6/108?

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More answers

anonymous
  • anonymous
i think u find all the possibilites that would make it 6, and then out of 36 (since that's the total number of sums.
anonymous
  • anonymous
n=36 so do we have to get the score on the upperface of both the cube be 6
anonymous
  • anonymous
1+5,2+4,3+3,4+2,5+1 (these are 5 possibilites) (5/36)^108 ---> i think :D
Zarkon
  • Zarkon
\[\frac{5}{36}\cdot 108=15\]
anonymous
  • anonymous
@zarkon is perfect
anonymous
  • anonymous
thank you!!!
anonymous
  • anonymous
yeah i meant to multiplication sign. sorry! yeah that means i got it right too!
anonymous
  • anonymous
welcome
anonymous
  • anonymous
haha i gave all of you guys medals!
anonymous
  • anonymous
now i will give u a medal
Zarkon
  • Zarkon
this is binomial...the mean is \(n\cdot p\)
anonymous
  • anonymous
zarkon's in the lead for medals :D
anonymous
  • anonymous
Yeahhh!!!! haha medals for evryone:D

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