anonymous
  • anonymous
true or false. the square root of x^2 = x is an identity
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
false
anonymous
  • anonymous
why
anonymous
  • anonymous
Because you the equation is not satisfied for every number you plug into it.

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anonymous
  • anonymous
\[2^2\neq2\]
anonymous
  • anonymous
ohhh sorry. I did not see the square root. Wait
anonymous
  • anonymous
\[\sqrt{x^2}=x\]
anonymous
  • anonymous
yeah
anonymous
  • anonymous
is not and identity either.
anonymous
  • anonymous
why?
anonymous
  • anonymous
\[\sqrt{(-1)^2}\neq-1\]
anonymous
  • anonymous
Because the equation is not always true.
anonymous
  • anonymous
This is an identity:\[\sin^2\theta+\cos^2\theta=1\]
anonymous
  • anonymous
No matter what value of theta you choose. the equation is always true.
anonymous
  • anonymous
ok thanks. how about this question: if f(x)=g(x) is an identity with domain of validity D, which of the following must be true? a) for any x in D, fx is defined b) for any x in D, gx is defined. c) for any x in D, fx=gx (you can choose all of them, two of them, one of them, none, etc whichever u think are true)
anonymous
  • anonymous
all of them are true.
anonymous
  • anonymous
in the case of your first question the domain of validity D = positive numbers and zero.
anonymous
  • anonymous
and then it is a identity.
anonymous
  • anonymous
ok thank you
anonymous
  • anonymous
You're welcome. By the way which course is this question from?
anonymous
  • anonymous
ohh ok. Have fun with that!

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