anonymous
  • anonymous
How do I find L? Area of the whole thing is 80m And W =6m See picture below.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1332694918733:dw|
anonymous
  • anonymous
well, areaa is L * w
anonymous
  • anonymous
80=6*L

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More answers

anonymous
  • anonymous
divide 80/6
anonymous
  • anonymous
80/6
anonymous
  • anonymous
I'm sorry the enclosed area is 80 meters.
anonymous
  • anonymous
Not the whole thing.
anonymous
  • anonymous
area, is area, it doesnt matter.
anonymous
  • anonymous
wait, the enclosed rectangle, or the right triangle?
anonymous
  • anonymous
The triangle is.
anonymous
  • anonymous
ok, then that is completely different. and there is no way to find L. Because the triangle can be area 80, and you can attach a rectangle that is as long as you like, it wont make a difference.
anonymous
  • anonymous
No, no the whole thing including the triangle is 80 meters. Sorry!
anonymous
  • anonymous
ooohhhh... hmm. so its L*w. AND the formula for a triangle
anonymous
  • anonymous
1/2 B*h
anonymous
  • anonymous
I just sectioned off the triangle for convenience sake. I knew I had to do something with that.
anonymous
  • anonymous
|dw:1332695388439:dw|
anonymous
  • anonymous
but there are too many unknowns to solve this..
ajprincess
  • ajprincess
1/2bh+lw=80 |dw:1332740378299:dw| here 6 is hypotenuse. I dnt thnk u cn multiply 6 by x.
anonymous
  • anonymous
unless the triangle is isosolis, so add the two sides with pythegooream theorem
anonymous
  • anonymous
oh... ya.. sorry. right.. its base*height. but we dont know eiither..
anonymous
  • anonymous
ajprincess, you are correct, it should be x times the square root of 36 - x^2
anonymous
  • anonymous
No I have to use inverse sin or something.... I have to find the area of the triangle and subtract it from 80 to find L
anonymous
  • anonymous
which makes x the square root of 18
ajprincess
  • ajprincess
we will have two variables x nd L
anonymous
  • anonymous
Liliy, I don't know how you got to square root of 18. You were right when you said there are too many unknowns. If the triangle was isosceles, it could be solved.
anonymous
  • anonymous
But there aren't too many unknowns. There is some law I have to use to find it. This is straight out of the book.
anonymous
  • anonymous
what's the thing?
anonymous
  • anonymous
so make hte triangle arccos(x/6)
anonymous
  • anonymous
A fence.
anonymous
  • anonymous
but why would that help you?
anonymous
  • anonymous
I found the answer in my notebook but my notes are quite confusing. L = 11.83
anonymous
  • anonymous
You have to divide the triangle up into two smaller triangles and use some weird math.
anonymous
  • anonymous
If that is a rectangle (four right angles), and that is an isosceles right triangle, you can bisect the triangle into two right isosceles triangles. Like so: |dw:1332698201254:dw| 6 * L + .5 * 6 * 3 = 80

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