anonymous
  • anonymous
limit as x approaches negative infinity 3x/(4x^2+10)^(1/2) why is this -3/2 instead of 3/2 if you end up with 3/(2+10^(1/2)/x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
why would you do that?
anonymous
  • anonymous
I thought you just divided by biggest x^n
Zarkon
  • Zarkon
\[\sqrt{4x^2+10}=\sqrt{x^2}\sqrt{4+\frac{10}{x^2}}=|x|\sqrt{4+\frac{10}{x^2}}\]

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Zarkon
  • Zarkon
then for \(x<0\) we have \[\frac{x}{|x|}=-1\]
TuringTest
  • TuringTest
dang, this is trickier than I anticipated I like Zarkon's way but I'm, trying to find another
anonymous
  • anonymous
gahh i hate theory, is there any other way to explain it having to do that would be a huge pain in the retriceon the test I'm going to have to remember that specifically. I didn't even know you could relate (x^2)^(1/2) to abs(x). How is that I get a 100% on the first test to not understanding what is going on at all...
TuringTest
  • TuringTest
actually the definition of \[|x|=\sqrt{x^2}\]that is a good thing to know in general
TuringTest
  • TuringTest
latex question: how do you write the defined as symbol?
Zarkon
  • Zarkon
this? \[\equiv\]
Zarkon
  • Zarkon
I usuallt just use := so \[|x|:=\sqrt{x^2}\]
anonymous
  • anonymous
I wish they would have taught us this earlier.... lol
Zarkon
  • Zarkon
usually it is written as \[|x|=\left\{\begin{matrix}x & \text{if}& x\ge0 \\-x & \text{if}&x<0\end{matrix}\right.\]
TuringTest
  • TuringTest
I mine wrong? I know they use it for some proofs
TuringTest
  • TuringTest
is*
Zarkon
  • Zarkon
\[|x|=\sqrt{x^2}\] is a valid definition

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