anonymous
  • anonymous
Find the real zeros y=x^3-7x-6 Please show work! Thank you. (:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Use synthetic division to check the factors that might multiply to -6 (the constant term). Make sure you pot a zero in there to represent the x^2 term. The answer falls right out.
anonymous
  • anonymous
|dw:1332706483701:dw|
anonymous
  • anonymous
3| 1 0 -7 -6 3 9 6 _____________ 1 3 2 | 0

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anonymous
  • anonymous
then do it again...
anonymous
  • anonymous
(x^2 - x - 6)(x + 1) = (x - 3)(x + 2)(x + 1) so zeros are 3, -2, -1
anonymous
  • anonymous
The quotient above factors to (x+2)(x+1), so y=(x-3)(x+2)(x+1) and the roots are x=-2,x=-1, x=3
anonymous
  • anonymous
Thank you! Must remember that method for the future...

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