anonymous
  • anonymous
Let (7,-2) be a point on the terminal side of theta. Find the exact values of sin, sec, and tan.
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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apoorvk
  • apoorvk
hmm... okay, the point is (7,-2). so tan(theta) is y/x = -2/7 here's how:|dw:1332708853604:dw| now you know tan(theta). think you can find out sin and cos?? P.S.- take care of the signs while writing final answers for sin and cos because the point lies in the fourth quadrant where only COS is positive!
anonymous
  • anonymous
does hypotenus= square root of 18?
anonymous
  • anonymous
wait square root of 53?

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apoorvk
  • apoorvk
yeah.... sqrt43. you did it!! almost there... now touch home base!!!!!!! :D
anonymous
  • anonymous
-2/sqroot of 43=sin sec= 7/sqroot 43?
Mertsj
  • Mertsj
|dw:1332710572295:dw|
apoorvk
  • apoorvk
almost... what you posted for sec is actually the cosine!!!!
Mertsj
  • Mertsj
Where are you getting 43? ma129115?
apoorvk
  • apoorvk
i guess that '43' was a typo ma??? it ll actually be sqrt53
anonymous
  • anonymous
I got square root of 53. lol and thanks i got the right answer.
apoorvk
  • apoorvk
anytime!!

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