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those are principal solutions.
DO NOT cancel of tanx from both sides, because if you do that you will miss one solution (that from tanx=0).. okay??
would pie and 2pi be another solution?
oh and can u help me with a couple of other identitres im having troublew with
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yeah... told you npi and (2n+1)pi/2 would be the genral solution, where n is any integer.!!!
yeah sure post as them as new questions on the page!!
okay here is another question whats the solution to 2cosx^2-cosx-1
okay leave that question can u answer this one
sorry i got busy.. you did that??? the one above??
can u solve the one i just send
yeah okay. so can you solve quadratic equations??? just substitute cosx with any variable, say 'm'
so you get m^2-2m+1=0
so, solve this and get m and then substitute m with cosx.
do the inverse to get x.
so is the last set of answers the answer
x=2n(pi), where n is any integer. because it forms:
so at x=0, 2pi, 4pi, 6pi....
so, umm.. i dont think the options are correct..