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shubham1

  • 4 years ago

Solve 3x2 = 12x.

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  1. shubham1
    • 4 years ago
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    I need 2 solutions

  2. philips13
    • 4 years ago
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    can you set it to 0 and factor it?

  3. mayayamfundo
    • 4 years ago
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    |dw:1332831788209:dw|is it like this?

  4. shubham1
    • 4 years ago
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    yes

  5. Akshay_Budhkar
    • 4 years ago
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    \[3x^2=12x \therefore 3x^2-12x=0 \therefore 3x(x-4)=0 \therefore x=0 or x=4\]

  6. mayayamfundo
    • 4 years ago
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    |dw:1332831859386:dw|if so, you will only have one solution. Which will look a bit something like this

  7. apoorvk
    • 4 years ago
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    NO NO No... dont cancel out x like that you ll miss the solution... bring them to one side and then take common!

  8. shubham1
    • 4 years ago
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    whats the answer apoorvk ill give a medal

  9. apoorvk
    • 4 years ago
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    |dw:1332713088143:dw|

  10. shubham1
    • 4 years ago
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    is that x = 0, x = 4

  11. apoorvk
    • 4 years ago
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    you dont need to offer medals, give them if you like, shubham... we do this to explain solutions to people and help 'em out, not to give them just the answers!! :)

  12. apoorvk
    • 4 years ago
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    yeah that is it.

  13. shubham1
    • 4 years ago
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    woo!

  14. mayayamfundo
    • 4 years ago
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    wait, is that an X between 3 and 2 on the left or its a multiplication sign?

  15. mayayamfundo
    • 4 years ago
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    You should have written it as 3x^2=12x. It got me confuzed, do that next time

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