xxfreshboy
Find the length of RQ
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xxfreshboy
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You know that RC = 13 cm and CQ = 13 cm
antonioms
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What do I do I am lost for sure
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I think you just have to use some trygonometry
xxfreshboy
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its geometry.
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You need to find RD and DQ first because RQ = RD + DQ
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\[DQ=\sqrt{13^2-5^2}\]
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and RD = DQ
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So \[RQ=2\sqrt{13^2-5^2}\]
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Thank you.
antonioms
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Thank you but I still don't know how you broke it down
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With some reasonable asumptions. that RQ is perpendicular to CD
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Then you get an Isosceles triangle.
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You know the value of two sides of triangle DCQ. So you can use the phytagorean theorem.
kell1170
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What kind of geometry is that? I'm in geometry and I don't remember that
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Well I my country is it taught as Modern Geometry.
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in my country*
kell1170
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Oh dear... Modern geometry? I can barely handle the geometry I'm in. o.o I know the pathagroeum therom though!
xxfreshboy
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first year geometry?
kell1170
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10th grade geometry. And first time taking it.
xxfreshboy
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ooo where are you up to n your class?
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Modern geometry is the study of triangles, and circles. Is not that difficult lady.
kell1170
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We're doing translations, transformations, rotations, etc. And I don't know. You either get geometry or you don't. We've learned about circles and triangles and it was hard for me to understand.
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Well that is far more advanced than modern geometry.
kell1170
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Really?
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Yes. Maybe you know it but you don't remember.
kell1170
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Most likely... haha do you know how many degrees are in a square?
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Yes I know.
kell1170
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What is it?
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360º
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Am I wrong?
kell1170
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Oh I don't know! I didn't know that's why I asked!
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Well you just have to remember that a squared is formed by perpendicular lines. So they form 90º on each vertex.
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90º + 90º + 90º + 90º = 360º
kell1170
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Well then yes, you're right. Thank you for your help! :D
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You're welcome.