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You know that RC = 13 cm and CQ = 13 cm

What do I do I am lost for sure

I think you just have to use some trygonometry

its geometry.

You need to find RD and DQ first because RQ = RD + DQ

\[DQ=\sqrt{13^2-5^2}\]

and RD = DQ

So \[RQ=2\sqrt{13^2-5^2}\]

Thank you.

Thank you but I still don't know how you broke it down

With some reasonable asumptions. that RQ is perpendicular to CD

Then you get an Isosceles triangle.

You know the value of two sides of triangle DCQ. So you can use the phytagorean theorem.

What kind of geometry is that? I'm in geometry and I don't remember that

Well I my country is it taught as Modern Geometry.

in my country*

first year geometry?

10th grade geometry. And first time taking it.

ooo where are you up to n your class?

Modern geometry is the study of triangles, and circles. Is not that difficult lady.

Well that is far more advanced than modern geometry.

Really?

Yes. Maybe you know it but you don't remember.

Most likely... haha do you know how many degrees are in a square?

Yes I know.

What is it?

360º

Am I wrong?

Oh I don't know! I didn't know that's why I asked!

90º + 90º + 90º + 90º = 360º

Well then yes, you're right. Thank you for your help! :D

You're welcome.