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You know that RC = 13 cm and CQ = 13 cm
What do I do I am lost for sure
I think you just have to use some trygonometry
You need to find RD and DQ first because RQ = RD + DQ
and RD = DQ
Thank you but I still don't know how you broke it down
With some reasonable asumptions. that RQ is perpendicular to CD
Then you get an Isosceles triangle.
You know the value of two sides of triangle DCQ. So you can use the phytagorean theorem.
What kind of geometry is that? I'm in geometry and I don't remember that
Well I my country is it taught as Modern Geometry.
in my country*
Oh dear... Modern geometry? I can barely handle the geometry I'm in. o.o I know the pathagroeum therom though!
first year geometry?
10th grade geometry. And first time taking it.
ooo where are you up to n your class?
Modern geometry is the study of triangles, and circles. Is not that difficult lady.
We're doing translations, transformations, rotations, etc. And I don't know. You either get geometry or you don't. We've learned about circles and triangles and it was hard for me to understand.
Well that is far more advanced than modern geometry.
Yes. Maybe you know it but you don't remember.
Most likely... haha do you know how many degrees are in a square?
Yes I know.
What is it?
Am I wrong?
Oh I don't know! I didn't know that's why I asked!
Well you just have to remember that a squared is formed by perpendicular lines. So they form 90º on each vertex.
90º + 90º + 90º + 90º = 360º
Well then yes, you're right. Thank you for your help! :D