anonymous
  • anonymous
Help simplifying trigonometric expressions:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[(1-\sin ^2x)/(sinx-cscx)\]
apoorvk
  • apoorvk
write csc(x) as 1/sinx. then multiply like binomial by binomial (like we did in quadratics). post and verify!!!
anonymous
  • anonymous
So like this? \[(1-\sin ^2x)/(\sin x-(1/\sin x))\] Should we convert the 1-sin^2x to cos^2x? Or just continue with \[(1-\sin^2x)((1/\sin x)-\sin x)\]

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phi
  • phi
out of curiosity, how did you get from (1−sin2x)/(sinx−(1/sinx)) to (1−sin2x)((1/sinx)−sinx) ?
anonymous
  • anonymous
Ooh, there was a mistake in multiplying by the reciprocal of the denominator.
phi
  • phi
How about re-writing 1/(sinx -1/sinx) as sin(x)/ ( sin^2 x - 1) (by multiplying by sinx/sinx)
phi
  • phi
or even better -sin(x)/ ( 1-sin^2 x ) by multiplying through by -1/-1
anonymous
  • anonymous
so the expression would simplify to \[-\sin x\]
phi
  • phi
that is what I got.
anonymous
  • anonymous
Thank you very much!

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