Here's the question you clicked on:
ttailyn
Find the derivative of: y=e^sec-1x (inverse trig functions)
yea thats how it looks.
\[{e^{\sec^{-1}(x)}} \over {\sqrt{1-{1\over x^2}} \ x^2}\]
http://www.wolframalpha.com/input/?i=deriv%28e%5EarcSec%28x%29%2C+x%29
thanks so much. this really helped! :)