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## culinarychick Group Title log (2328) = 2x? Can someone show me how to work this problem 2 years ago 2 years ago

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1. y2o2 Group Title

$x = {\log(2328) \over 2} = {1\over2 }\log(2328) = \log(\sqrt{2328}) ≈1.6834914879889...$