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culinarychick

  • 4 years ago

log (2328) = 2x? Can someone show me how to work this problem

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  1. y2o2
    • 4 years ago
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    \[x = {\log(2328) \over 2} = {1\over2 }\log(2328) = \log(\sqrt{2328}) ≈1.6834914879889...\]

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