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calyne
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complicated calculus problem: derivative of g(x) = (2ra^(rx)+n)^p ?
 2 years ago
 2 years ago
calyne Group Title
complicated calculus problem: derivative of g(x) = (2ra^(rx)+n)^p ?
 2 years ago
 2 years ago

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calyne Group TitleBest ResponseYou've already chosen the best response.1
the textbook answer is g'(x) = 2r^(2) p (ln a) (2ra^(rx) + n)^(p1) a^(rx) i can get pretty close but don't know where the hell the exponent 2 comes from
 2 years ago
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