anonymous
  • anonymous
Ryder drew a scale drawing of the rectangular pool in his backyard using a scale of 1 in = 4 ft. He wants to add a border around the perimeter of the pool using 12-in square tiles. If the length of the drawing of the pool is 6 in, and the width of the drawing is 3 in, how many tiles does Ryder need for the border?
Physics
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
well, since 12 inches = 1 foot, then each tile is scaled to 1/4 of an inch
amistre64
  • amistre64
of course this might be simpler if we scale inches to feet :)
anonymous
  • anonymous
1# Find the perimeter of the pool in inches (2 x length + 2 x width). 2# Convert the total from inches into feet (total in inches x 4 feet). 3# Knowing that 12 inches is 1 foot, divide the total perimeter in feet by the length (in feet) of one of the sides of the square tile.

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radar
  • radar
Keeping to the scale. The length which is 6 in will require 6/.25 + 2 or 26 tile for each side that will require a total of 52 tile, but the width is 3in 3/.25 =12 tiles for each end thats 24+52 or 76 tiles. the "+2" on the length will put an extending tile on each side of the length, so the tiles on the width can butt up to them.|dw:1332730020719:dw|

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