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snsdfb
factor each polynomial completely. 3x^2+ 30x+ 75
Hey guys, please explain how you got here to help snsdfb understand the process. Thanks!
each term in the trinomial is factorable by 3, so pull out the 3.
once you do that youll have 3(x^2+10x+25)
so to factor that, find two terms that will multiple to 25, but add to 10, which is 5.
so youll have 3(x+5)(x+5). to check your work, simply multiple the parenthesis and then distribute the 3
thank you can you explain how to factor 5m^2- 20n^2?
both of those terms are divisible by 5. so pull out the 5 from each term. youll have 5(m^2 - 4n^2)
since you have more than one variable you cannot factor any further than that.
okay got it. how about 2k^3-36k^2+162k?
each term is divisible by 2, so divide each term by 2 and youll get 2(k^3-18k^2+81)
x is also a common factor, so take out an x from each term
so youll have 2k(K^2-18k+81)
so now like before find two terms that multiply to positive 81, but add to negative 18, which is -9
so your final answer would be 2k(k-9)(k-9). to check your answer simply multiply the parenthesis then distribute 2k to each term
thank you. 12x^3-20x^2+30x-50?
pull out a 2x from each term: 2x(6x^2+15x-25)
since you have a leading coefficient you can't accurately an answer that has 2 parenthesis. so you will have to plug in each value into the quadratic equation. the quadratic equation is [-b+/-(sqrt((b^2)-(4*a*c)))]/(2*a)
i need to factor the polynomial
once you plug in all the values your answer will be -15+/--5root33 all over 12
that polynomial is not factorable.
factor the polynomial. 6x^2-2x-20
pull out the 2: 2(3x^2-x-10) using the 3 find two numbers that will multiply to -10 but add to -1: (x-2)(3x+5) im not here to do your math homework, if youre having trouble with the process of getting the answer just ask me question about that.