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IsTim
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Which pairs of planes are parallel and distinct and which are conincident?
2x+4y7z2=0
4x+6y14z8=0
 2 years ago
 2 years ago
IsTim Group Title
Which pairs of planes are parallel and distinct and which are conincident? 2x+4y7z2=0 4x+6y14z8=0
 2 years ago
 2 years ago

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IsTim Group TitleBest ResponseYou've already chosen the best response.0
I tried looking through my notes and textbook for this one, but unless there is a direct connection, I don't understand how to apply it to this question.
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
I managed to answer some unrelated questions beforehand, but I don't know how I managed to solve them...
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
So I figured out the normals were [2,3,7] and [4,6,14]
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
I can see that I just have to multiply 2,3,7 by 2 to get the other plane. So would that be conidental or parallel and distinct?
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
that should be parallel and distinct.. if u can just multiply them by a scalar, but i suck at this, so idk.. @Mertsj @Zarkon
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
@amistre64 @satellite73 @myininaya
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
@LagrangeSon678
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
Wait. Maybe I'll try something out here.
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
how is [2,3,7] the normal vector?
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
Er, I just looked at my notes and inferred that...
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
if 2x+4y7z2=0 is your equation then <2,4,7> is the normal vector
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
Zarkon to the rescue!!!!
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
Ok, got that. For the other then, it must be 4,6,14?
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
So from this, how would I determine the answer? Or do I need more?
 2 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.2
if the planes are parrallel then the cross product of their normal vectors should be 0
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
two plane are parallel iff their normal vectors are parellel
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
I'll try that cross product thing. Thanks guys. I'lll cry out if I have a problem.
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
two non zero vectors \(\vec{v}\) and \(\vec{u}\) are parallel iff \(\vec{v}=c\vec{u}\) for some scalar \(c\)
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
is one of the vectors a constant multiple of the other?
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
The first one, multiplied by 2, equals the second one.
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
IT seemed so...
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
if you have the equations 2x+4y7z2=0 4x+6y14z8=0 then you have the normal vectors <2,4,7> and <4,6,14> are these constant multiples of each other?
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
That 4y was suppose to be a 3y....
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
I did mistype that. No wonder my confusion. And probably yours...
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
then <4,6,14>=2<2,3,7> and so they are parallel...and therefore their planes are parallel
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
And distinct??
 2 years ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
Awesome. Thank you. This was relatively simple after all...
 2 years ago
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