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claireshowers

  • 4 years ago

8^(y - 2) = 2^y

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  1. Lukecrayonz
    • 4 years ago
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    y=3

  2. Lukecrayonz
    • 4 years ago
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    This was just using my brain, sorry.

  3. Lukecrayonz
    • 4 years ago
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    I know you set the bases equal, then put the extra numbers to distribute to the powers, then set the powers equal.

  4. dpaInc
    • 4 years ago
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    8^(y - 2) = 2^y (2^3)^(y - 2) = 2^y 2^3(y - 2) = 2^y 3(y - 2) = y now solve...

  5. Lukecrayonz
    • 4 years ago
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    Yep ;P What he did.

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