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Look for two numbers that multiply to -180 and add to -8 (-18 and 10). then factor by grouping and finally use the zero factor property.
i got (x^2+10) (-18-180) =0
Close just remember that when you rewrite it, it is x^2+10x-18x-180 and then factor in groups
(12x^2+10x)+(-18x-180) You have this first, now can you factor out the like terms in each set of brackets?
3x? is the like term?
no, for the first bracket 2x will be the like term because 2x goes into 12x^2 and 10x
Sorry I have a typo it should be -15 not 180
You want to split the middle term of 12x^2-8x-15 as 12x^2-18x+10x-15
for the second brackets the common factor would be 3 right?
Correct -3 :)
so, is that the answer? -3 and 2? Or i have to do more? Because of the 0?
So far we have this 2x(6x+5)-(6x+5)=0 We can factor the 6x+5 to get (6x+5)(2x-1)=0 Then we can solve for x
What answers do you get?
x=5/6 and x=-1/2???
that's not right is it?
No, right numbers just the wrong sign. for the 2x-1 bracket I have 2x-1=0 2x=1 x=1/2 Do you see this? 6x+5=0 6x=-5 x=-5/6
Really close though, good work
so i basically got it right, i just had to switch the negative and pos. signs? Thanks for helping me!
No worries :)
do you think you could help me with x^2-29x+204?
sure I posted on that question lets move to it now