anonymous
  • anonymous
Given triangle ABC, where ray of BD is an altitude and AD=CD. Prove triangle ADB is congruent to triangle CDB. Write in statement and proof form....
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
The altitude is always perpendicular to the base so angle ADB is the same as CDB. Sides AD = DC (given), and DB = DB (reflexive) so ADB is congruent to CDB by side-angle-side.
anonymous
  • anonymous
(1)ABD=CBD --> bisected by BD (2)BD=BD --> reflexive property (3)AD=CD --> given

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Directrix
  • Directrix
1. Segment BD is an altitude of Triangle ABC, drawn to Segment AC  Given 2. Segment BD is perpendicular to Segment AC  Definition of Altitude 3. AD = DC  Given 4. Segment BD is the perpendicular-bisector of Segment AC  Definition of Perpendicular-Bisector of a Segment 5. AB = CB  All points on the perpendicular-bisector of a segment are equidistant from the endpoints of the segment 6. Segment BD is congruent to Segment BD  Reflexive Property 7. Triangle ADB is congruent to Triangle CDB  SSS Postulate Alternate Proof 1. Segment BD is an altitude of Triangle ABC, drawn to Segment AC  Given 2. Segment BD is perpendicular to Segment AC  Definition of Altitude 3. Angle BDA is congruent to Angle BDC  Perpendicular line form right angles; Right angles are congruent 4. AD = DC  Given 5. Segment BD is congruent to Segment BD  Reflexive Property 6. Triangle ADB is congruent to Triangle CDB  SAS Postulate

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