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so you want to find the derivative using the definition of derivative...
let f(x) = 1/(x-1). give me f(x + h) = to do this, wherever you see an x, put in an (x+h)
Im at: ((1/(x+h-1))-(1/x-1))/h Where do I simplify from there.. ??
can you simplify the top? |dw:1332745618103:dw|
thats where im stuck. multiplying by (x+h-!) is ovbiously not working out.. ?
crap... forgot you can multiply the fraction within a fraction and not affect the denominator of the overall fraction. -.-
now cancel the h and simplify...
|dw:1332745962826:dw| whats this?? is that an arrow pointing to h?
wait nvm on the top circle -.-
the first circled h is the denominator of the whole fraction. the second h is "negative" h... i simplified the expression circled just to the left of it.
this is what you should get when it gets simplified. |dw:1332746179705:dw|
how does h*-h = -1?
no, i subtracted the numerators... |dw:1332746328418:dw|
i know. so the numerator is -h.
yes... now cancel the h's.
did that wrong, again... -.-|dw:1332746513831:dw|
it's ok... take your time. it takes a while...
:P alright. so lim f(x+h) as h->0, so h=0. 1/((x-1)(x+1) ?
not quite.. try it again. you almost got it...
do i need to multiple the denominator?
just stick in h=0 and simplify
dear god i am full of simple math errors... -.- its past bedtime by a little. can you tell? -.-
you got it!!! :)
oops don't forget the negative.
EEEEEEEEEEEEEEEEEEERGHH lol thx
np. the other should be easy. just holler.
I truly hope that you understand my workings..
thanks a ton! xD!
welcome 'a ton' :D
Nah... my wrong workings... please correct it : all the +1 after x+h should be -1 for (1) That is x+h+1 -> x+h-1
yeah thats fine, i was just wondering about the second to last line of (2)?
why is 3x multiplied by (0) ? 3x(0) as in the second number