anonymous
  • anonymous
Use the gradient to find the directional derivative of the function at P in the direction of Q. f(x,y) = sin2xcosy, P(pi,0),Q(pi/2,pi)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
For vector PQ I got -pi/2i-pi
experimentX
  • experimentX
how did you get that?
anonymous
  • anonymous
I took pi/2-pi , and pi-0 to get -pi/2i-pij

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experimentX
  • experimentX
yeah ...okay that right!!! i understand!!
anonymous
  • anonymous
then would the unit vector where u=v/||v|| be -pi/2i-pij/[squarert(pi^2/4+pi^2)]?
experimentX
  • experimentX
yeah ... that would be correct!!
experimentX
  • experimentX
okay, i think i get it d(PQ)/dr = gradient of f(x,y) .dot. unit vector
anonymous
  • anonymous
yeah thats the formula.
experimentX
  • experimentX
you have the unit vector above ... the gradient is i 2 cos(2x).cos(x) - j sin(2x).sin(x)
anonymous
  • anonymous
yeah well i got thetaf(x,y)=2cos2xcosyi-sin2xsinyj
experimentX
  • experimentX
i haven't calculated, must be something like -pi*cos(2x)(cosy)/|v|+pi*sin(2x) (sinx)/|v| since it is a dot product, it should be scalar

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