anonymous
  • anonymous
What's wrong with\[\int_{-1}^1\frac{dx}{x}=\ln|1|-\ln|-1|=0\]?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Yes, but I'm told that this is incorrect.
Callisto
  • Callisto
I guess you have to 'separate' the integral into 2 parts (from -1->0 and 0->1) and use lim to find the area?! It seems i've encountered some problem like this and you have to use limit to do it..
anonymous
  • anonymous
Gotcha.

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anonymous
  • anonymous
Because you're integrating \(\ln x\) in a region underfined for the reals.
Callisto
  • Callisto
the term is something like 'improper integral'.. I'm not sure and i couldn't find that post.. sorry :(
Callisto
  • Callisto
Hmm the post is this http://openstudy.com/study#/updates/4f6ac4a6e4b014cf77c7e6e1 That's something similar to your problem
myininaya
  • myininaya
Yes @callisto 's is right You have to break this up
myininaya
  • myininaya
If both of the parts converge then find the sum of what both converge to and that is your answer
myininaya
  • myininaya
If one part diverges then the whole thing diverges
myininaya
  • myininaya
\[\lim_{a \rightarrow 0^-} \int\limits_{-1}^{a} \frac{1}{x} dx+\lim_{b \rightarrow 0^+} \int\limits_{b}^{1} \frac{1}{x} dx\]
myininaya
  • myininaya
|dw:1332759212188:dw|

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